Lebanon, Nebraska

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Lebanon is a village in Red Willow County, Nebraska, United States. The population was 70 at the 2000 census.


Lebanon is located at 40°2′57″N 100°16′35″W / 40.04917°N 100.27639°W / 40.04917; -100.27639 (40.049211, -100.276348)[3].

According to the United States Census Bureau, the village has a total area of 0.2 square miles (0.4 km²), all of it land.


As of the census[1] of 2000, there were 70 people, 34 households, and 21 families residing in the village. The population density was 436.5 people per square mile (168.9/km²). There were 48 housing units at an average density of 299.3/sq mi (115.8/km²). The racial makeup of the village was 100.00% White.

There were 34 households out of which 20.6% had children under the age of 18 living with them, 58.8% were married couples living together, and 35.3% were non-families. 35.3% of all households were made up of individuals and 26.5% had someone living alone who was 65 years of age or older. The average household size was 2.06 and the average family size was 2.59.

In the village the population was spread out with 20.0% under the age of 18, 7.1% from 18 to 24, 21.4% from 25 to 44, 24.3% from 45 to 64, and 27.1% who were 65 years of age or older. The median age was 47 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the village was $19,688, and the median income for a family was $30,833. Males had a median income of $33,750 versus $8,125 for females. The per capita income for the village was $15,406. There were 16.7% of families and 25.9% of the population living below the poverty line, including 55.0% of under eighteens and none of those over 64.


Indianola | McCook

Bartley | Danbury | Lebanon

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