Lindon, Utah

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Lindon is a city in Utah County, Utah, United States. It is part of the ProvoOrem, Utah Metropolitan Statistical Area. The population was 8,363 at the 2000 census.



Lindon is located at 40°20′19″N 111°42′58″W / 40.33861°N 111.71611°W / 40.33861; -111.71611 (40.338552, -111.716206).[3]

According to the United States Census Bureau, the city has a total area of 8.6 square miles (22.2 km²), of which, 8.4 square miles (21.8 km²) of it is land and 0.2 square miles (0.5 km²) of it (2.21%) is water.


As of the census[1] of 2000, there were 8,363 people, 1,935 households, and 1,789 families residing in the city. The population density was 996.0 people per square mile (384.4/km²). There were 1,974 housing units at an average density of 235.1/sq mi (90.7/km²). The racial makeup of the city was 95.67% White, 0.20% African American, 0.22% Native American, 0.69% Asian, 0.16% Pacific Islander, 1.84% from other races, and 1.22% from two or more races. Hispanic or Latino of any race were 3.32% of the population.

There were 1,935 households out of which 64.0% had children under the age of 18 living with them, 86.6% were married couples living together, 4.5% had a female householder with no husband present, and 7.5% were non-families. 5.9% of all households were made up of individuals and 2.5% had someone living alone who was 65 years of age or older. The average household size was 4.29 and the average family size was 4.46.

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