Lovell, Wyoming

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Lovell is a town in Big Horn County, Wyoming, United States. The population was 2,281 at the 2000 census.



Lovell is located at 44°50′12″N 108°23′32″W / 44.83667°N 108.39222°W / 44.83667; -108.39222 (44.836787, -108.392180)[3].

According to the United States Census Bureau, the town has a total area of 1.1 square miles (2.8 km²), all of it land.


As of the census[1] of 2000, there were 2,281 people, 896 households, and 613 families residing in the town. The population density was 2,141.6 people per square mile (823.1/km²). There were 1,013 housing units at an average density of 951.1/sq mi (365.5/km²). The racial makeup of the town was 90.93% White, 0.04% African American, 0.70% Native American, 0.18% Asian, 0.13% Pacific Islander, 5.66% from other races, and 2.37% from two or more races. Hispanic or Latino of any race were 9.16% of the population.

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