Midvale, Utah

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Midvale is a city in Salt Lake County, Utah, United States. It is part of the Salt Lake City, Utah Metropolitan Statistical Area. The population was 27,029 at the 2000 census.

Contents

Geography

Midvale is located at 40°36′50″N 111°53′18″W / 40.61389°N 111.88833°W / 40.61389; -111.88833 (40.613990, -111.888214).[3]

According to the United States Census Bureau, the city has a total area of 5.8 square miles (15.1 km²), all of it land.

Demographics

As of the census[1] of 2000, there were 27,029 people, 10,089 households, and 6,638 families residing in the city. The population density was 4,627.4 people per square mile (1,787.0/km²). There were 10,730 housing units at an average density of 1,837.0/sq mi (709.4/km²). The racial makeup of the city was 82.44% White, 1.18% African American, 1.29% Native American, 1.85% Asian, 0.58% Pacific Islander, 9.96% from other races, and 2.71% from two or more races. Hispanic or Latino of any race were 20.77% of the population.

There were 10,089 households out of which 31.7% had children under the age of 18 living with them, 47.8% were married couples living together, 12.7% had a female householder with no husband present, and 34.2% were non-families. 25.3% of all households were made up of individuals and 6.5% had someone living alone who was 65 years of age or older. The average household size was 2.66 and the average family size was 3.19.

In the city the population was spread out with 25.8% under the age of 18, 16.7% from 18 to 24, 31.8% from 25 to 44, 16.6% from 45 to 64, and 9.0% who were 65 years of age or older. The median age was 28 years. For every 100 females there were 102.8 males. For every 100 females age 18 and over, there were 100.7 males.

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