Montrose, South Dakota

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Montrose is a city in McCook County, South Dakota, United States. The population was 460 at the 2000 census.



Montrose is located at 43°41′58″N 97°11′9″W / 43.69944°N 97.18583°W / 43.69944; -97.18583 (43.699453, -97.185858)[4].

According to the United States Census Bureau, the city has a total area of 0.4 square miles (1.1 km²), all of it land.

Montrose has been assigned the ZIP code 57048 and the FIPS place code 43500.


As of the census[2] of 2000, there were 460 people, 195 households, and 124 families residing in the city. The population density was 1,133.7 people per square mile (433.2/km²). There were 202 housing units at an average density of 497.8/sq mi (190.2/km²). The racial makeup of the city was 98.70% White, 0.87% Native American, 0.43% from other races. Hispanic or Latino of any race were 1.09% of the population.

There were 195 households out of which 26.7% had children under the age of 18 living with them, 53.8% were married couples living together, 6.2% had a female householder with no husband present, and 35.9% were non-families. 31.3% of all households were made up of individuals and 17.4% had someone living alone who was 65 years of age or older. The average household size was 2.36 and the average family size was 2.98.

In the city the population was spread out with 25.0% under the age of 18, 8.3% from 18 to 24, 28.9% from 25 to 44, 18.3% from 45 to 64, and 19.6% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 88.5 males. For every 100 females age 18 and over, there were 88.5 males.

The median income for a household in the city was $31,250, and the median income for a family was $39,583. Males had a median income of $30,385 versus $19,886 for females. The per capita income for the city was $15,233. About 3.5% of families and 11.8% of the population were below the poverty line, including 8.5% of those under age 18 and 18.9% of those age 65 or over.

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