Mount Orab, Ohio

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Mount Orab is a village in Brown County, Ohio, United States. The population was 2,307 at the 2000 census.



Mount Orab is located at 39°1′47″N 83°55′30″W / 39.02972°N 83.925°W / 39.02972; -83.925 (39.029613, -83.924918).[3]

According to the United States Census Bureau, the village has a total area of 3.8 mi² (9.8 km²), all land.


As of the census[2] of 2000, there were 2,307 people, 879 households, and 639 families residing in the village. The population density was 607.7 people per square mile (234.4/km²). There were 932 housing units at an average density of 245.5/sq mi (94.7/km²). The racial makeup of the village was 99.22% White, 0.13% African American, 0.22% Native American, 0.04% Asian, and 0.39% from two or more races. Hispanic or Latino of any race were 0.22% of the population.

There were 879 households out of which 40.6% had children under the age of 18 living with them, 51.5% were married couples living together, 16.6% had a female householder with no husband present, and 27.3% were non-families. 23.4% of all households were made up of individuals and 11.1% had someone living alone who was 65 years of age or older. The average household size was 2.61 and the average family size was 3.05.

In the village the population was spread out with 30.8% under the age of 18, 9.8% from 18 to 24, 30.6% from 25 to 44, 17.5% from 45 to 64, and 11.3% who were 65 years of age or older. The median age was 30 years. For every 100 females there were 86.7 males. For every 100 females age 18 and over, there were 80.5 males.

The median income for a household in the village was $33,798, and the median income for a family was $42,938. Males had a median income of $33,672 versus $21,339 for females. The per capita income for the town was $16,483. About 12.5% of families and 14.6% of the population were below the poverty line, including 20.2% of those under age 18 and 8.7% of those age 65 or over.

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