Napoleon, North Dakota

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Napoleon is a city in Logan County, North Dakota in the United States. It is the county seat of Logan County[3]. The population was 857 at the 2000 census. Napoleon was founded in 1885.



Napoleon is located at 46°30′17″N 99°46′1″W / 46.50472°N 99.76694°W / 46.50472; -99.76694 (46.504657, -99.766979)[4].

According to the United States Census Bureau, the city has a total area of 1.4 square miles (3.6 km²), all of it land.


At the 2000 census[1], there were 857 people, 367 households and 238 families residing in the city. The population density was 616.8 per square mile (238.1/km²). There were 420 housing units at an average density of 302.3/sq mi (116.7/km²). The racial makeup of the city was 98.83% White, 0.35% Asian, 0.23% from other races, and 0.58% from two or more races. Hispanic or Latino of any race were 0.47% of the population.

There were 367 households of which 22.3% had children under the age of 18 living with them, 58.0% were married couples living together, 4.9% had a female householder with no husband present, and 35.1% were non-families. 31.6% of all households were made up of individuals and 19.3% had someone living alone who was 65 years of age or older. The average household size was 2.24 and the average family size was 2.82.

Age distribution was 22.1% under the age of 18, 3.7% from 18 to 24, 18.7% from 25 to 44, 22.3% from 45 to 64, and 33.3% who were 65 years of age or older. The median age was 50 years. For every 100 females there were 90.9 males. For every 100 females age 18 and over, there were 85.6 males.

The median household income was $28,167, and the median family income was $36,042. Males had a median income of $28,036 versus $20,000 for females. The per capita income for the city was $16,208. About 5.9% of families and 8.8% of the population were below the poverty line, including 5.4% of those under age 18 and 15.3% of those age 65 or over.

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