Newport, Indiana

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Newport is a town in Vermillion Township, Vermillion County, Indiana, United States. The population was 578 at the 2000 census. The town is the county seat of Vermillion County[3].



Newport is located at 39°53′6″N 87°24′23″W / 39.885°N 87.40639°W / 39.885; -87.40639 (39.884869, -87.406301)[4].

According to the United States Census Bureau, the town has a total area of 0.8 square miles (2.1 km²), all of it land.


As of the census[1] of 2000, there were 578 people, 237 households, and 162 families residing in the town. The population density was 714.8 people per square mile (275.5/km²). There were 253 housing units at an average density of 312.9/sq mi (120.6/km²). The racial makeup of the town was 97.58% White, 0.35% Native American, 0.87% Asian, and 1.21% from two or more races. Hispanic or Latino of any race were 1.21% of the population.

There were 237 households out of which 32.9% had children under the age of 18 living with them, 53.6% were married couples living together, 9.7% had a female householder with no husband present, and 31.6% were non-families. 27.8% of all households were made up of individuals and 12.7% had someone living alone who was 65 years of age or older. The average household size was 2.44 and the average family size was 2.94.

In the town the population was spread out with 24.7% under the age of 18, 8.0% from 18 to 24, 29.1% from 25 to 44, 23.4% from 45 to 64, and 14.9% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 107.2 males. For every 100 females age 18 and over, there were 97.7 males.

The median income for a household in the town was $33,571, and the median income for a family was $36,389. Males had a median income of $36,518 versus $20,104 for females. The per capita income for the town was $16,771. About 5.9% of families and 9.1% of the population were below the poverty line, including 7.9% of those under age 18 and 9.5% of those age 65 or over.

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