North Freedom, Wisconsin

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North Freedom is a village in Sauk County, Wisconsin, United States, along the Baraboo River. The population was 649 at the 2000 census.




North Freedom is located at 43°27′39″N 89°51′57″W / 43.46083°N 89.86583°W / 43.46083; -89.86583 (43.460843, -89.865862).[3]

According to the United States Census Bureau, the village has a total area of 0.9 square miles (2.3 km²), of which, 0.9 square miles (2.3 km²) of it is land and 1.14% is water.


As of the census[2] of 2000, there were 649 people, 238 households, and 164 families residing in the village. The population density was 745.9 people per square mile (288.0/km²). There were 252 housing units at an average density of 289.6/sq mi (111.8/km²). The racial makeup of the village was 98.31% White, 0.77% Native American, and 0.92% from two or more races. Hispanic or Latino of any race were 1.08% of the population.

There were 238 households out of which 39.1% had children under the age of 18 living with them, 58.4% were married couples living together, 5.9% had a female householder with no husband present, and 30.7% were non-families. 25.6% of all households were made up of individuals and 11.8% had someone living alone who was 65 years of age or older. The average household size was 2.73 and the average family size was 3.28.

In the village the population was spread out with 30.7% under the age of 18, 7.1% from 18 to 24, 31.4% from 25 to 44, 18.5% from 45 to 64, and 12.3% who were 65 years of age or older. The median age was 33 years. For every 100 females there were 102.8 males. For every 100 females age 18 and over, there were 93.1 males.

The median income for a household in the village was $37,273, and the median income for a family was $41,818. Males had a median income of $32,500 versus $20,000 for females. The per capita income for the village was $14,354. About 5.4% of families and 11.3% of the population were below the poverty line, including 8.5% of those under age 18 and 10.1% of those age 65 or over.

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