North Randall, Ohio

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North Randall is a village in Cuyahoga County, Ohio, United States. The population was 906 at the 2000 census.



North Randall is located at 41°25′52″N 81°31′50″W / 41.43111°N 81.53056°W / 41.43111; -81.53056 (41.431203, -81.530582)[4].

According to the United States Census Bureau, the village has a total area of 0.8 square miles (2.0 km²), all of it land.


As of the census[2] of 2000, there were 906 people, 465 households, and 211 families residing in the village. The population density was 1,158.8 people per square mile (448.5/km²). There were 490 housing units at an average density of 626.7/sq mi (242.6/km²). The racial makeup of the village was 21.08% White, 71.74% African American, 0.33% Native American, 0.99% Asian, 2.98% from other races, and 2.87% from two or more races. Hispanic or Latino of any race were 7.28% of the population.

There were 465 households out of which 20.4% had children under the age of 18 living with them, 22.6% were married couples living together, 18.7% had a female householder with no husband present, and 54.6% were non-families. 51.0% of all households were made up of individuals and 13.8% had someone living alone who was 65 years of age or older. The average household size was 1.80 and the average family size was 2.62.

In the village the population was spread out with 16.3% under the age of 18, 10.4% from 18 to 24, 32.1% from 25 to 44, 24.7% from 45 to 64, and 16.4% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 94.8 males. For every 100 females age 18 and over, there were 94.9 males.

The median income for a household in the village was $28,235, and the median income for a family was $38,580. Males had a median income of $31,154 versus $25,417 for females. The per capita income for the village was $20,938. About 5.6% of families and 11.4% of the population were below the poverty line, including 9.3% of those under age 18 and 7.3% of those age 65 or over.

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