Petersburg, Indiana

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Petersburg is a city in Washington Township, Pike County, Indiana, United States. The population was 2,570 at the 2000 census. The city is the county seat of Pike County[3].

Petersburg is part of the Jasper Micropolitan Statistical Area.



Petersburg is located at 38°29′30″N 87°16′49″W / 38.49167°N 87.28028°W / 38.49167; -87.28028 (38.491653, -87.280372)[4].

According to the United States Census Bureau, the city has a total area of 1.5 square miles (3.8 km²), all of it land.


As of the census[1] of 2000, there were 2,570 people, 1,092 households, and 670 families residing in the city. The population density was 1,755.3 people per square mile (679.6/km²). There were 1,228 housing units at an average density of 838.7/sq mi (324.7/km²). The racial makeup of the city was 99.07% White, 0.19% African American, 0.04% Native American, 0.04% Pacific Islander, 0.08% from other races, and 0.58% from two or more races. Hispanic or Latino of any race were 0.39% of the population.

There were 1,092 households out of which 24.7% had children under the age of 18 living with them, 47.1% were married couples living together, 11.1% had a female householder with no husband present, and 38.6% were non-families. 35.5% of all households were made up of individuals and 17.9% had someone living alone who was 65 years of age or older. The average household size was 2.24 and the average family size was 2.88.

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