Polk, Nebraska

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Polk is a village in Polk County, Nebraska, United States. The population was 322 at the 2000 census.


Polk is located at 41°4′34″N 97°47′6″W / 41.07611°N 97.785°W / 41.07611; -97.785 (41.076243, -97.785010)[3].

According to the United States Census Bureau, the village has a total area of 0.5 square miles (1.3 km²).0.5 square miles (1.3 km²) of it is land and none of it is covered by water.


As of the census[1] of 2000, there were 322 people, 152 households, and 86 families residing in the village. The population density was 658.4 people per square mile (253.7/km²). There were 190 housing units at an average density of 388.5/sq mi (149.7/km²). The racial makeup of the village was 100.00% White. Hispanic or Latino of any race were 0.62% of the population.

There were 152 households out of which 21.1% had children under the age of 18 living with them, 51.3% were married couples living together, 4.6% had a female householder with no husband present, and 42.8% were non-families. 40.1% of all households were made up of individuals and 26.3% had someone living alone who was 65 years of age or older. The average household size was 2.12 and the average family size was 2.86.

In the village the population was spread out with 19.9% under the age of 18, 4.7% from 18 to 24, 21.7% from 25 to 44, 20.8% from 45 to 64, and 32.9% who were 65 years of age or older. The median age was 47 years. For every 100 females there were 96.3 males. For every 100 females age 18 and over, there were 89.7 males.

The median income for a household in the village was $28,056, and the median income for a family was $38,472. Males had a median income of $26,389 versus $18,500 for females. The per capita income for the village was $15,670. About 4.4% of families and 5.4% of the population were below the poverty line, including 6.2% of those under age 18 and 8.4% of those age 65 or over.


Osceola | Stromsburg

Polk | Shelby

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