Purple Sage, Wyoming

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Purple Sage is a census-designated place (CDP) in Sweetwater County, Wyoming, United States. The population was 413 at the 2000 census.



Purple Sage is located at 41°32′55″N 109°19′43″W / 41.548512°N 109.328618°W / 41.548512; -109.328618Coordinates: 41°32′55″N 109°19′43″W / 41.548512°N 109.328618°W / 41.548512; -109.328618 (41.548512, -109.328618)[3].

According to the United States Census Bureau, the CDP has a total area of 0.9 square miles (2.4 km²), all of it land.


As of the census[1] of 2000, there were 413 people, 131 households, and 99 families residing in the CDP. The population density was 445.8 people per square mile (171.5/km²). There were 160 housing units at an average density of 172.7/sq mi (66.4/km²). The racial makeup of the CDP was 70.22% White, 3.15% African American, 0.73% Native American, 0.24% Asian, 11.14% from other races, and 14.53% from two or more races. Hispanic or Latino of any race were 18.40% of the population.

There were 131 households out of which 50.4% had children under the age of 18 living with them, 55.7% were married couples living together, 13.0% had a female householder with no husband present, and 23.7% were non-families. 14.5% of all households were made up of individuals and 1.5% had someone living alone who was 65 years of age or older. The average household size was 3.15 and the average family size was 3.56.

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