Roland, Oklahoma

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Roland is a town in Sequoyah County, Oklahoma, United States. It is part of the Fort Smith, Arkansas-Oklahoma Metropolitan Statistical Area. The population was 2,842 at the 2000 census.

Contents

Geography

Roland is located at 35°25′5″N 94°30′53″W / 35.41806°N 94.51472°W / 35.41806; -94.51472 (35.418013, -94.514815)[3].

According to the United States Census Bureau, the town has a total area of 20.7 square miles (6.9 km²), of which, 2.6 square miles (6.8 km²) of it is land and 0.04 square miles (0.1 km²) of it (0.75%) is water.

Demographics

As of the census[1] of 2000, there were 2,842 people, 1,055 households, and 815 families residing in the town. The population density was 1,075.6 people per square mile (415.6/km²). There were 1,132 housing units at an average density of 428.4/sq mi (165.6/km²). The racial makeup of the town was 73.89% White, 4.57% African American, 11.22% Native American, 0.14% Asian, 0.04% Pacific Islander, 0.77% from other races, and 9.36% from two or more races. Hispanic or Latino of any race were 3.10% of the population.

There were 1,055 households out of which 41.0% had children under the age of 18 living with them, 56.8% were married couples living together, 17.2% had a female householder with no husband present, and 22.7% were non-families. 19.5% of all households were made up of individuals and 8.9% had someone living alone who was 65 years of age or older. The average household size was 2.69 and the average family size was 3.09.

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