Rolfe, Iowa

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Rolfe is a city in Pocahontas County, Iowa, United States. The population was 675 at the 2000 census.

Contents

Geography

Rolfe is located at 42°48′52″N 94°31′48″W / 42.81444°N 94.53°W / 42.81444; -94.53 (42.814333, -94.530029)[1].

According to the United States Census Bureau, the city has a total area of 1.0 square miles (2.7 km²), all of it land.

Demographics

As of the census[2] of 2000, there were 675 people, 296 households, and 185 families residing in the city. The population density was 643.9 people per square mile (248.2/km²). There were 326 housing units at an average density of 311.0/sq mi (119.9/km²). The racial makeup of the city was 97.63% White, 0.44% African American, 0.30% Native American, 0.15% Asian, 0.44% from other races, and 1.04% from two or more races. Hispanic or Latino of any race were 1.04% of the population.

There were 296 households out of which 24.3% had children under the age of 18 living with them, 52.4% were married couples living together, 7.4% had a female householder with no husband present, and 37.2% were non-families. 34.5% of all households were made up of individuals and 21.6% had someone living alone who was 65 years of age or older. The average household size was 2.20 and the average family size was 2.85.

In the city the population was spread out with 22.7% under the age of 18, 6.4% from 18 to 24, 21.0% from 25 to 44, 22.7% from 45 to 64, and 27.3% who were 65 years of age or older. The median age was 45 years. For every 100 females there were 94.0 males. For every 100 females age 18 and over, there were 86.4 males.

The median income for a household in the city was $24,861, and the median income for a family was $32,500. Males had a median income of $28,750 versus $19,167 for females. The per capita income for the city was $12,426. About 9.7% of families and 12.5% of the population were below the poverty line, including 15.2% of those under age 18 and 11.9% of those age 65 or over.

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