Roosevelt, New York

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{household, population, female}
{mi², represent, 1st}

Roosevelt is a hamlet (and census-designated place) in Nassau County, New York, United States. The population was 15,854 at the 2000 census.

Roosevelt is in the town of Hempstead.



Roosevelt is located at 40°40′45″N 73°35′08″W / 40.679172°N 73.585471°W / 40.679172; -73.585471.[1]

According to the United States Census Bureau, the CDP has a total area of 4.6 km2 (1.8 mi²). 4.6 km2 (1.8 mi2) of it is land and 0.56% is water.


As of the census[2] of 2000, there were 15,854 people, 4,061 households, and 3,362 families residing in the CDP. The population density was 3,438.9/km2 (8,916.8/mi2). There were 4,234 housing units at an average density of 918.4/km2 (2,381.3/mi2). The racial makeup of the CDP was 3.97% White, 79.02% African American, 0.46% Native American, 0.49% Asian, 0.05% Pacific Islander, 8.33% from other races, and 3.69% from two or more races. Hispanic or Latino of any race were 16.22% of the population.

There were 4,061 households out of which 38.3% had children under the age of 18 living with them, 44.2% were married couples living together, 30.3% had a female householder with no husband present, and 17.2% were non-families. 12.0% of all households were made up of individuals and 4.1% had someone living alone who was 65 years of age or older. The average household size was 3.88 and the average family size was 3.98.

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