Roosevelt, Utah

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Roosevelt is a city in Duchesne County, Utah, United States. The population was 4,299 at the 2000 census.

The proper pronunciation of the city's name (IPA: /ˈroʊzəvɛlt/) is based on how President Theodore Roosevelt pronounced his name: according to the man himself, "pronounced as if it was spelled 'Rosavelt.'[3]



Roosevelt is located at 40°17′55″N 109°59′39″W / 40.29861°N 109.99417°W / 40.29861; -109.99417 (40.298721, -109.994035).[4]

According to the United States Census Bureau, the city has a total area of 5.2 square miles (13.6 km²), all of it land.


As of the census[1] of 2000, there were 4,299 people, 1,380 households, and 1,095 families residing in the city. The population density was 818.6 people per square mile (316.2/km²). There were 1,566 housing units at an average density of 298.2/sq mi (115.2/km²). The racial makeup of the city was 86.58% White American, 0.19% Black or African American, 8.14% Native American, 0.21% Asian American, none Pacific Islander American, 1.74% from other races, and 3.14% from two or more races. Hispanic or Latino of any race were 3.88% of the population.

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