Rosedale, California

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Rosedale is a census-designated place (CDP) in Kern County, California, United States. The population was 8,445 at the 2000 census. Formerly a country town 10 miles (16 km) west of Bakersfield, it is now completely surrounded by suburban sprawl and now has the highest household income in Kern County, according to Census estimates.

Contents

Geography

Rosedale is located at 35°23′01″N 119°08′43″W / 35.38361°N 119.14528°W / 35.38361; -119.14528.[1]

According to the United States Census Bureau, the CDP has a total area of 37.9 square miles (98.1 km²), all of it land.

History

Rosedale was founded in 1891 as a colony of English farmers.[2] A post office operated at Rosedale from 1891 to 1913.[2]

Demographics

As of the census[3] of 2000, there were 8,445 people, 2,566 households, and 2,304 families residing in the CDP. The population density was 223.1 people per square mile (86.1/km²). There were 2,776 housing units at an average density of 73.3/sq mi (28.3/km²). The racial makeup of the CDP was 88.98% White, 1.22% Black or African American, 1.22% Native American, 1.36% Asian, 0.04% Pacific Islander, 4.30% from other races, and 2.89% from two or more races. 11.00% of the population were Hispanic or Latino of any race.

There were 2,566 households out of which 49.6% had children under the age of 18 living with them, 80.4% were married couples living together, 5.8% had a female householder with no husband present, and 10.2% were non-families. 7.8% of all households were made up of individuals and 2.6% had someone living alone who was 65 years of age or older. The average household size was 3.28 and the average family size was 3.45.

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