Sacramento, Kentucky

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Sacramento is a city in McLean County, Kentucky, United States. The population was 517 at the 2000 census. It is included in the Owensboro, Kentucky Metropolitan Statistical Area.



Sacramento is located at 37°24′59″N 87°16′4″W / 37.41639°N 87.26778°W / 37.41639; -87.26778 (37.416489, -87.267839)[1].

According to the United States Census Bureau, the city has a total area of 0.4 square miles (1.1 km²), all of it land.


As of the census[2] of 2000, there were 517 people, 219 households, and 150 families residing in the city. The population density was 1,229.5 people per square mile (475.3/km²). There were 238 housing units at an average density of 566.0/sq mi (218.8/km²). The racial makeup of the city was 93.81% White, 3.09% African American, 0.77% Native American, 0.58% from other races, and 1.74% from two or more races. Hispanic or Latino of any race were 0.97% of the population.

There were 219 households out of which 27.4% had children under the age of 18 living with them, 49.3% were married couples living together, 15.1% had a female householder with no husband present, and 31.5% were non-families. 26.9% of all households were made up of individuals and 12.8% had someone living alone who was 65 years of age or older. The average household size was 2.36 and the average family size was 2.77.

In the city the population was spread out with 22.2% under the age of 18, 10.3% from 18 to 24, 25.7% from 25 to 44, 26.7% from 45 to 64, and 15.1% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 95.8 males. For every 100 females age 18 and over, there were 89.6 males.

The median income for a household in the city was $23,889, and the median income for a family was $27,344. Males had a median income of $22,045 versus $22,083 for females. The per capita income for the city was $11,811. About 19.1% of families and 21.8% of the population were below the poverty line, including 25.8% of those under age 18 and 21.7% of those age 65 or over.

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