San Antonio Heights, California

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San Antonio Heights is a census-designated place (CDP) in San Bernardino County, California, United States. The population was 3,122 at the 2000 census.



San Antonio Heights is an affluent area located at 34°9′11″N 117°39′41″W / 34.15306°N 117.66139°W / 34.15306; -117.66139 (34.153008, -117.661433)[1]. The area is directly north of the city of Upland.

According to the United States Census Bureau, the CDP has a total area of 3.7 km² (1.4 mi²). 3.6 km² (1.4 mi²) of it is land and 0.1 km² (0.04 mi²) of it (1.41%) is water.


As of the census[2] of 2000, there were 3,122 people, 1,081 households, and 891 families residing in the CDP. The population density was 861.0/km² (2,228.7/mi²). There were 1,121 housing units at an average density of 309.2/km² (800.3/mi²). The racial makeup of the CDP was 85.4% White, 1.4% African American, 0.7% Native American, 6.1% Asian, <0.1% Pacific Islander, 3.1% from other races, and 3.3% from two or more races. Hispanic or Latino of any race were 10.5% of the population.

There were 1,081 households out of which 35.0% had children under the age of 18 living with them, 70.3% were married couples living together, 8.0% had a female householder with no husband present, and 17.5% were non-families. 12.6% of all households were made up of individuals and 5.4% had someone living alone who was 65 years of age or older. The average household size was 2.9 and the average family size was 3.1.

In the CDP the population was spread out with 24.4% under the age of 18, 7.3% from 18 to 24, 24.1% from 25 to 44, 29.5% from 45 to 64, and 14.6% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 94.5 males. For every 100 females age 18 and over, there were 95.8 males.

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