Scarville, Iowa

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Scarville is a city in Winnebago County, Iowa, United States. The population was 97 at the 2000 census.


Scarville is located at 43°28′14″N 93°36′59″W / 43.47056°N 93.61639°W / 43.47056; -93.61639 (43.470519, -93.616480)[1].

According to the United States Census Bureau, the city has a total area of 0.1 square miles (0.3 km²), all of it land.


As of the census[2] of 2000, there were 97 people, 41 households, and 25 families residing in the city. The population density was 997.4 people per square mile (374.5/km²). There were 42 housing units at an average density of 431.8/sq mi (162.2/km²). The racial makeup of the city was 95.88% White and 4.12% Native American.

There were 41 households out of which 34.1% had children under the age of 18 living with them, 48.8% were married couples living together, 7.3% had a female householder with no husband present, and 36.6% were non-families. 34.1% of all households were made up of individuals and 9.8% had someone living alone who was 65 years of age or older. The average household size was 2.37 and the average family size was 2.92.

In the city the population was spread out with 32.0% under the age of 18, 4.1% from 18 to 24, 24.7% from 25 to 44, 23.7% from 45 to 64, and 15.5% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 90.2 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the city was $40,139, and the median income for a family was $38,750. Males had a median income of $30,000 versus $21,500 for females. The per capita income for the city was $18,949. There were 6.3% of families and 6.9% of the population living below the poverty line, including 6.7% of under eighteens and none of those over 64.


Buffalo Center | Forest City‡ | Lake Mills | Leland | Rake | Scarville | Thompson

‡This populated place also has portions in an adjacent county or counties

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