Shawneetown, Illinois

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Shawneetown is a city in Gallatin County, Illinois, United States. The population was 1,410 at the 2000 census. It is the county seat of Gallatin County.[1] See Old Shawneetown, Illinois for the historical village.

Contents

Geography

Shawneetown is located at 37°42′53″N 88°11′00″W / 37.714701°N 88.183465°W / 37.714701; -88.183465.[2]

According to the United States Census Bureau, the city has a total area of 1.2 square miles (3.2 km²), of which, 1.2 square miles (3.1 km²) of it is land and 0.04 square miles (0.1 km²) of it (75.694%) is water.

History

The present town was established in 1937 after flooding on the Ohio River inundated what is now Old Shawneetown, Illinois.[citation needed]

Demographics

As of the census[3] of 2000, there were 1,410 people, 632 households, and 389 families residing in the city. The population density was 1,181.8 people per square mile (457.5/km²). There were 693 housing units at an average density of 580.8/sq mi (224.8/km²). The racial makeup of the city was 96.17% White, 0.50% African American, 2.34% Native American, 0.14% Pacific Islander, 0.28% from other races, and 0.57% from two or more races. Hispanic or Latino of any race were 1.70% of the population.

There were 632 households out of which 27.1% had children under the age of 18 living with them, 44.5% were married couples living together, 13.6% had a female householder with no husband present, and 38.4% were non-families. 35.1% of all households were made up of individuals and 18.7% had someone living alone who was 65 years of age or older. The average household size was 2.20 and the average family size was 2.83.

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