Sherwood, Defiance County, Ohio

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Sherwood is a village in Defiance County, Ohio, United States. The population was 801 at the 2000 census.



Sherwood is located at 41°17′12″N 84°33′06″W / 41.286690°N 84.551628°W / 41.286690; -84.551628.[3]

According to the United States Census Bureau, the village has a total area of 1.5 square miles (3.8 km2), of which, 1.4 square miles (3.7 km2) of it is land and 0.69% is water.


As of the census[2] of 2000, there were 801 people, 301 households, and 227 families residing in the village. The population density was 554.4 people per square mile (214.8/km2). There were 315 housing units at an average density of 218.0/sq mi (84.5/km2). The racial makeup of the village was 96.00% White, 0.75% African American, 0.37% Native American, 1.87% from other races, and 1.00% from two or more races. Hispanic or Latino of any race were 3.50% of the population.

There were 301 households out of which 34.6% had children under the age of 18 living with them, 60.8% were married couples living together, 10.3% had a female householder with no husband present, and 24.3% were non-families. 21.3% of all households were made up of individuals and 9.6% had someone living alone who was 65 years of age or older. The average household size was 2.66 and the average family size was 3.04.

In the village the population was spread out with 27.3% under the age of 18, 8.5% from 18 to 24, 29.5% from 25 to 44, 22.2% from 45 to 64, and 12.5% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 89.8 males. For every 100 females age 18 and over, there were 90.8 males.

The median income for a household in the village was $39,135, and the median income for a family was $42,188. Males had a median income of $32,130 versus $23,500 for females. The per capita income for the village was $16,212. About 10.9% of families and 12.5% of the population were below the poverty line, including 14.7% of those under age 18 and 17.3% of those age 65 or over.

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