Sherwood, North Dakota

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Sherwood is a city in Renville County, North Dakota, in the United States. The population was 255 as of the 2000 census. It is part of the Minot Micropolitan Statistical Area. It was founded by Sherwood Sleeper in 1904.

Sherwood's weather station has one of the lowest (if not the lowest) yearly precipitation levels in North Dakota, with an annual normal of 13.13 inches (1971-2000 period).[3]

Sherwood is also designated by the U.S. Customs and Border Protection agency as a port of entry between the United States and Canada.[4]

Contents

Geography

Sherwood is located at 48°57′41″N 101°37′55″W / 48.96139°N 101.63194°W / 48.96139; -101.63194 (48.961469, -101.631889)[5].

According to the United States Census Bureau, the city has a total area of 0.3 square miles (0.8 km²), all of it land.

Demographics

As of the census[1] of 2000, there were 255 people, 117 households, and 65 families residing in the city. The population density was 802.2 people per square mile (307.7/km²). There were 138 housing units at an average density of 434.1/sq mi (166.5/km²). The racial makeup of the city was 98.04% White, 1.18% Native American, and 0.78% from two or more races.

There were 117 households out of which 28.2% had children under the age of 18 living with them, 47.0% were married couples living together, 5.1% had a female householder with no husband present, and 43.6% were non-families. 42.7% of all households were made up of individuals and 24.8% had someone living alone who was 65 years of age or older. The average household size was 2.18 and the average family size was 3.08.

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