Shiloh, DeKalb County, Alabama

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Shiloh is a town in DeKalb County, Alabama, United States. At the 2000 census the population was 289. Shiloh is located on top of Sand Mountain.


Shiloh is located at 34°27′56″N 85°52′38″W / 34.46556°N 85.87722°W / 34.46556; -85.87722 (34.465555, -85.877311).[1]

According to the U.S. Census Bureau, the town has a total area of 1.7 square miles (4.5 km²), all of it land.


As of the census[2] of 2000, there were 289 people, 116 households, and 80 families residing in the town. The population density was 168.5 people per square mile (64.9/km²). There were 135 housing units at an average density of 78.7/sq mi (30.3/km²). The racial makeup of the town was 97.58% White, 1.38% Native American, 0.35% from other races, and 0.69% from two or more races. Hispanic or Latino of any race were 0.69% of the population.

There were 116 households out of which 30.2% had children under the age of 18 living with them, 55.2% were married couples living together, 11.2% had a female householder with no husband present, and 30.2% were non-families. 25.9% of all households were made up of individuals and 9.5% had someone living alone who was 65 years of age or older. The average household size was 2.49 and the average family size was 3.00.

In the town the population was spread out with 22.8% under the age of 18, 10.7% from 18 to 24, 31.1% from 25 to 44, 20.1% from 45 to 64, and 15.2% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 86.5 males. For every 100 females age 18 and over, there were 84.3 males.

The median income for a household in the town was $34,861, and the median income for a family was $36,696. Males had a median income of $29,219 versus $25,893 for females. The per capita income for the town was $28,431. About 4.3% of families and 9.7% of the population were below the poverty line, including 8.2% under the age of 18 and 15.2% ages 65 or older.


Coordinates: 34°27′56″N 85°52′38″W / 34.465555°N 85.877311°W / 34.465555; -85.877311

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