Shorewood, Wisconsin

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Shorewood is a village in Milwaukee County, Wisconsin, United States. The population was 13,763 at the 2000 census.

Contents

Geography

Shorewood is located at 43°05′31″N 87°53′11″W / 43.092061°N 87.886333°W / 43.092061; -87.886333 (43.092061, -87.886333).[3]

Nestled between the Milwaukee River and Lake Michigan, Shorewood is bordered by the City of Milwaukee to the south and west and Whitefish Bay to the north. According to the United States Census Bureau, the village has a total area of 1.6 square miles (4.1 km2), all of it land.

Demographics

As of the census[2] of 2000, there were 13,763 people, 6,539 households, and 3,328 families residing in the village. The population density was 8,599.5 people per square mile (3,321.2/km2). There were 6,696 housing units at an average density of 4,183.9/sq mi (1,615.8/km2). The racial makeup of the village was 91.43% White, 2.41% African American, 0.23% Native American, 3.19% Asian, 0.04% Pacific Islander, 0.84% from other races, and 1.85% from two or more races. Hispanic or Latino of any race were 2.51% of the population.

There were 6,539 households out of which 25.3% had children under the age of 18 living with them, 40.8% were married couples living together, 7.9% had a female householder with no husband present, and 49.1% were non-families. 39.5% of all households were made up of individuals and 12.3% had someone living alone who was 65 years of age or older. The average household size was 2.08 and the average family size was 2.87.

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