Silverton, Ohio

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Silverton is a city in Hamilton County, Ohio, United States. The city was formed out of Columbia and Sycamore Townships, but withdrew from both and formed a paper township. The population was 5,178 at the 2000 census.



Silverton is located at 39°11′28″N 84°24′10″W / 39.19111°N 84.40278°W / 39.19111; -84.40278 (39.191160, -84.402762)[3].

According to the United States Census Bureau, the city has a total area of 1.1 square miles (2.9 km²), all of it land.


As of the census[2] of 2000, there were 5,178 people, 2,534 households, and 1,256 families residing in the city. The population density was 4,647.8 people per square mile (1,801.1/km²). There were 2,662 housing units at an average density of 2,389.4/sq mi (925.9/km²). The racial makeup of the city was 45.52% White, 50.31% African American, 0.19% Native American, 0.81% Asian, 0.04% Pacific Islander, 0.77% from other races, and 2.36% from two or more races. Hispanic or Latino of any race were 1.16% of the population.

There were 2,534 households out of which 19.5% had children under the age of 18 living with them, 32.2% were married couples living together, 14.4% had a female householder with no husband present, and 50.4% were non-families. 45.4% of all households were made up of individuals and 12.5% had someone living alone who was 65 years of age or older. The average household size was 2.00 and the average family size was 2.84.

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