Sioux Center, Iowa

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Sioux Center is a city in Sioux County, Iowa, United States. The population was 6,002 at the 2000 census; a special census in 2005 counted 6,327 residents.[1]



Sioux Center is located at 43°4′36″N 96°10′24″W / 43.07667°N 96.17333°W / 43.07667; -96.17333 (43.076546, -96.173214)[2].

According to the United States Census Bureau, the city has a total area of 5.3 square miles (13.7 km²), all of it land.

Sioux Center is 1,445 feet above sea level. It is located on the north to south ridge, or spine, of western Iowa. The eastern side of Sioux Center drains to the Floyd River. The western side of Sioux Center drains to the Big Sioux River. This "divide" is profoundly unnoticeable. The area within a ten mile radius of Sioux Center has been divided into sections of a square mile each. The gravel and paved roads marking the sections do not swerve or contour for the slight hills or valleys. North of town, the BNSF railroad has a very broad curve in which it crosses highway 75 twice in the space of one mile.


As of the census[3] of 2000, there were 6,002 people, 1,831 households, and 1,351 families residing in the city. The population density was 1,134.9 people per square mile (438.1/km²). There were 1,933 housing units at an average density of 365.5/sq mi (141.1/km²). The racial makeup of the city was 96.58% White, 0.15% African American, 0.10% Native American, 0.85% Asian, 0.03% Pacific Islander, 1.62% from other races, and 0.67% from two or more races. Hispanic or Latino of any race were 4.67% of the population, but this population continues to grow.

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