Smackover, Arkansas

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Smackover is a city in Union County, Arkansas. According to the 2006 Census Bureau estimates, the population of the city stands at 1,929.[1]

The name Smackover comes from an anglicization of the French "Sumac Couvert" which translates to "covered in sumac".[2] I do not know how to enter this change, but here goes: In 1951 I took a course "History of the English Language" while a student at the Journalism School of the University of Missouri. The professor was talking about the strange origins of many United States place names. One that he mentioned was Smackover, Arkansas. He said the name came by Americans corrupting speech of the first white men to frequent that place, French trappers and traders who took the French chemin couvert or "covered path" which was the nature of one of the many ages-old Indian trails through the heavily forested areas there.

Contents

Geography

Smackover is located at 33°21′41″N 92°43′40″W / 33.36139°N 92.72778°W / 33.36139; -92.72778 (33.361525, -92.727855)[3].

According to the United States Census Bureau, the city has a total area of 4.2 square miles (11.0 km²), all of it land. Smackover is also an important town in South Arkansas.

Demographics

As of the census[4] of 2000, there were 2,005 people, 794 households, and 565 families residing in the city. The population density was 471.9 people per square mile (182.1/km²). There were 915 housing units at an average density of 215.3/sq mi (83.1/km²). The racial makeup of the city was 72.57% White, 26.28% Black or African American, 0.10% Native American, 0.05% Asian, 0.05% Pacific Islander, and 0.95% from two or more races. 0.25% of the population were Hispanic or Latino of any race.

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