South Bay, Florida

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South Bay is a city in Palm Beach County, Florida, United States. It is the westernmost municipality in the South Florida metropolitan area. The population was 3,859 at the 2000 census. As of 2007, the population recorded by the U.S. Census Bureau is 4,506.[4] While the current estimates place South Bay's population in the incorporated city limits at more than 4,000 people, surrounding areas increase the population figures to 54,000 people in a 25-mile radius and more than 1.4 million in a 50-mile radius.



South Bay is located at 26°39′59″N 80°43′8″W / 26.66639°N 80.71889°W / 26.66639; -80.71889 (26.666487, -80.718985)[5], near the southern bank of Lake Okeechobee.

According to the United States Census Bureau, the city has a total area of 9.6 km² (3.7 mi²). 7.0 km² (2.7 mi²) of it is land and 2.6 km² (1.0 mi²) of it (26.95%) is water.


As of the census[2] of 2000, there were 3,859 people, 805 households, and 644 families residing in the city. The population density was 549.8/km² (1,425.4/mi²). There were 935 housing units at an average density of 133.2/km² (345.4/mi²). The racial makeup of the city was 24.23% White (of which 12.5% were Non-Hispanic Whites,)[6] 66.93% African American, 0.29% Native American, 0.26% Asian, 0.03% Pacific Islander, 5.83% from other races, and 2.44% from two or more races. Hispanic or Latino of any race were 19.56% of the population.

There were 805 households out of which 41.7% had children under the age of 18 living with them, 39.5% were married couples living together, 32.0% had a female householder with no husband present, and 20.0% were non-families. 15.8% of all households were made up of individuals and 4.7% had someone living alone who was 65 years of age or older. The average household size was 3.39 and the average family size was 3.76.

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