Staplehurst, Nebraska

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Staplehurst is a village in Seward County, Nebraska, United States. It is part of the Lincoln, Nebraska Metropolitan Statistical Area. The population was 270 at the 2000 census.



Staplehurst is located at 40°58′29″N 97°10′20″W / 40.97472°N 97.17222°W / 40.97472; -97.17222 (40.974812, -97.172346)[3].

According to the United States Census Bureau, the village has a total area of 0.1 square miles (0.4 km²), all of it land.


As of the census[1] of 2000, there were 270 people, 108 households, and 73 families residing in the village. The population density was 1,983.7 people per square mile (744.6/km²). There were 116 housing units at an average density of 852.3/sq mi (319.9/km²). The racial makeup of the village was 97.41% White, 0.37% Asian, and 2.22% from two or more races. Hispanic or Latino of any race were 0.37% of the population.

There were 108 households out of which 28.7% had children under the age of 18 living with them, 55.6% were married couples living together, 7.4% had a female householder with no husband present, and 32.4% were non-families. 28.7% of all households were made up of individuals and 14.8% had someone living alone who was 65 years of age or older. The average household size was 2.50 and the average family size was 3.11.

In the village the population was spread out with 24.4% under the age of 18, 10.7% from 18 to 24, 25.6% from 25 to 44, 25.9% from 45 to 64, and 13.3% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 110.3 males.

The median income for a household in the village was $38,542, and the median income for a family was $42,361. Males had a median income of $28,125 versus $18,125 for females. The per capita income for the village was $14,449. About 7.4% of families and 10.3% of the population were below the poverty line, including 17.6% of those under the age of eighteen and 12.9% of those sixty five or over.

Noted native

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