Underhill, Wisconsin

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Underhill is a town in Oconto County, Wisconsin, United States. The population was 846 at the 2000 census. The unincorporated community of Underhill is located in the town.



The town was named after William Underhill, a settler from Vermont.[3]


According to the United States Census Bureau, the town has a total area of 35.6 square miles (92.2 km²), of which, 35.1 square miles (90.8 km²) of it is land and 0.5 square miles (1.4 km²) of it (1.52%) is water.


At the 2000 census[2], there were 846 people, 329 households and 235 families residing in the town. The population density was 24.1 per square mile (9.3/km²). There were 468 housing units at an average density of 13.3/sq mi (5.2/km²). The racial makeup of the town was 93.50% White, 3.43% Native American, 0.35% Asian, and 2.72% from two or more races.Hispanic or Latino of any race were 0.12% of the population.

There were 329 households of which 30.1% had children under the age of 18 living with them, 62.6% were married couples living together, 5.8% had a female householder with no husband present, and 28.3% were non-families. 22.5% of all households were made up of individuals and 7.6% had someone living alone who was 65 years of age or older. The average household size was 2.57 and the average family size was 3.03.

Age distribution was 25.5% under the age of 18, 7.0% from 18 to 24, 28.4% from 25 to 44, 23.8% from 45 to 64, and 15.4% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 109.9 males. For every 100 females age 18 and over, there were 108.6 males.

The median household income was $31,905, and the median family income was $39,844. Males had a median income of $31,250 versus $20,521 for females. The per capita income for the town was $16,503. About 6.2% of families and 10.8% of the population were below the poverty line, including 13.8% of those under age 18 and 4.4% of those age 65 or over.


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