Wann, Oklahoma

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Wann is a town in Nowata County, Oklahoma, United States. The population was 132 at the 2000 census. Wann is famous for the 'Six Flag Poles Over Wann America'.


Wann is located at 36°54′54″N 95°48′18″W / 36.915°N 95.805°W / 36.915; -95.805 (36.915015, -95.805012)[3].

According to the United States Census Bureau, the town has a total area of 0.2 square miles (0.4 km²), all of it land.


As of the census[1] of 2000, there were 132 people, 50 households, and 35 families residing in the town. The population density was 758.6 people per square mile (299.8/km²). There were 59 housing units at an average density of 339.1/sq mi (134.0/km²). The racial makeup of the town was 68.18% White, 21.21% Native American, and 10.61% from two or more races. Hispanic or Latino of any race were 7.58% of the population.

There were 50 households out of which 36.0% had children under the age of 18 living with them, 60.0% were married couples living together, 8.0% had a female householder with no husband present, and 30.0% were non-families. 30.0% of all households were made up of individuals and 10.0% had someone living alone who was 65 years of age or older. The average household size was 2.64 and the average family size was 3.09.

In the town the population was spread out with 34.1% under the age of 18, 5.3% from 18 to 24, 25.0% from 25 to 44, 24.2% from 45 to 64, and 11.4% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 94.1 males. For every 100 females age 18 and over, there were 107.1 males.

The median income for a household in the town was $27,917, and the median income for a family was $33,750. Males had a median income of $26,250 versus $21,250 for females. The per capita income for the town was $13,512. There were 9.7% of families and 9.3% of the population living below the poverty line, including no under eighteens and 15.0% of those over 64.



Delaware | Lenapah | New Alluwe | South Coffeyville | Wann

Childers | Watova

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