Yatesville, Georgia

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Yatesville is a town in Upson County, Georgia, United States. The population was 408 at the 2000 census.


Yatesville is located at 32°54′46″N 84°8′33″W / 32.91278°N 84.1425°W / 32.91278; -84.1425 (32.912663, -84.142393)[3].

According to the United States Census Bureau, the town has a total area of 0.9 square miles (2.3 km²), of which, 0.9 square miles (2.3 km²) of it is land and 1.14% is water.


As of the census[1] of 2000, there were 408 people, 158 households and 124 families residing in the town. The population density was 465.0 people per square mile (179.0/km²). There were 175 housing units at an average density of 199.5/sq mi (76.8/km²). The racial makeup of the town was 75.74% White, 23.77% African American, 0.25% Native American, 0.25% from other races. Hispanic or Latino of any race were 0.74% of the population.

There were 159 households out of which 30.8% had children under the age of 18 living with them, 58.5% were married couples living together, 11.9% had a female householder with no husband present, and 22.0% were non-families. 19.5% of all households were made up of individuals and 11.3% had someone living alone who was 65 years of age or older. The average household size was 2.57 and the average family size was 2.91.

In the town the population was spread out with 21.8% under the age of 18, 9.1% from 18 to 24, 29.2% from 25 to 44, 22.5% from 45 to 64, and 17.4% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 90.7 males. For every 100 females age 18 and over, there were 87.6 males.

The median income for a household in the town was $38,750, and the median income for a family was $38,500. Males had a median income of $30,096 versus $25,500 for females. The per capita income for the town was $21,762. About 9.2% of families and 9.4% of the population were below the poverty line, including 16.5% of those under age 18 and none of those age 65 or over.




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