Yorktown, Texas

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Yorktown is a city in DeWitt County, Texas, United States. The population was 2,271 at the 2000 census.

Contents

Geography

Yorktown is located at 28°59′00″N 97°30′09″W / 28.983196°N 97.502415°W / 28.983196; -97.502415Coordinates: 28°59′00″N 97°30′09″W / 28.983196°N 97.502415°W / 28.983196; -97.502415 (28.983196, -97.502415).[3]

According to the United States Census Bureau, the city has a total area of 1.7 square miles (4.5 km²), all of it land.

Demographics

As of the census[1] of 2000, there were 2,271 people, 864 households, and 584 families residing in the city. The population density was 1,318.1 people per square mile (509.8/km²). There were 1,048 housing units at an average density of 608.3/sq mi (235.3/km²). The racial makeup of the city was 79.83% White, 2.99% African American, 0.40% Native American, 15.32% from other races, and 1.45% from two or more races. Hispanic or Latino of any race were 37.60% of the population.

There were 864 households out of which 30.7% had children under the age of 18 living with them, 50.7% were married couples living together, 12.5% had a female householder with no husband present, and 32.3% were non-families. 29.9% of all households were made up of individuals and 18.9% had someone living alone who was 65 years of age or older. The average household size was 2.54 and the average family size was 3.15.

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