Arapaho, Oklahoma

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Arapaho is a town in Custer County, Oklahoma, United States. The population was 748 at the 2000 census. It is the county seat of Custer County[3]. Its name derives from the Arapaho Indians.



Arapaho is located at 35°34′37″N 98°57′45″W / 35.57694°N 98.9625°W / 35.57694; -98.9625 (35.577014, -98.962370)[4].

According to the United States Census Bureau, the town has a total area of 0.7 square miles (1.8 km²), all of it land.



As of the census[1] of 2000, there were 748 people, 265 households, and 205 families residing in the town. The population density was 1,067.4 people per square mile (412.6/km²). There were 300 housing units at an average density of 428.1/sq mi (165.5/km²). The racial makeup of the town was 87.03% White, 1.20% African American, 5.88% Native American, 1.07% Asian, 2.41% from other races, and 2.41% from two or more races. Hispanic or Latino of any race were 5.61% of the population.

There were 265 households out of which 41.9% had children under the age of 18 living with them, 60.0% were married couples living together, 12.1% had a female householder with no husband present, and 22.3% were non-families. 21.1% of all households were made up of individuals and 11.7% had someone living alone who was 65 years of age or older. The average household size was 2.66 and the average family size was 3.07.

In the town the population was spread out with 29.1% under the age of 18, 7.9% from 18 to 24, 28.6% from 25 to 44, 23.5% from 45 to 64, and 10.8% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 97.9 males. For every 100 females age 18 and over, there were 97.8 males.

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