Devol, Oklahoma

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Devol is a town in Cotton County, Oklahoma, United States. The population was 150 at the 2000 census.



Devol is located at 34°11′38″N 98°35′26″W / 34.19389°N 98.59056°W / 34.19389; -98.59056 (34.193755, -98.590533)[3].

According to the United States Census Bureau, the town has a total area of 0.5 square miles (1.3 km²), all of it land.


As of the census[1] of 2000, there were 150 people, 62 households, and 40 families residing in the town. The population density was 302.0 people per square mile (115.8/km²). There were 68 housing units at an average density of 136.9/sq mi (52.5/km²). The racial makeup of the town was 90.67% White, 4.67% Native American, and 4.67% from two or more races. Hispanic or Latino of any race were 8.67% of the population.

There were 62 households out of which 30.6% had children under the age of 18 living with them, 56.5% were married couples living together, 8.1% had a female householder with no husband present, and 33.9% were non-families. 33.9% of all households were made up of individuals and 16.1% had someone living alone who was 65 years of age or older. The average household size was 2.42 and the average family size was 3.12.

In the town the population was spread out with 22.7% under the age of 18, 10.7% from 18 to 24, 29.3% from 25 to 44, 21.3% from 45 to 64, and 16.0% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 114.3 males. For every 100 females age 18 and over, there were 107.1 males.

The median income for a household in the town was $35,313, and the median income for a family was $46,563. Males had a median income of $23,750 versus $28,333 for females. The per capita income for the town was $14,792. There were 2.1% of families and 9.4% of the population living below the poverty line, including 2.0% of under eighteens and 36.0% of those over 64.


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