Elizabethtown, Indiana

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Elizabethtown is a town in Sand Creek Township, Bartholomew County, Indiana, United States. The population was 391 at the 2000 census. It is part of the Columbus, Indiana metropolitan statistical area.

Contents

Geography

Elizabethtown is located at 39°8′5″N 85°48′45″W / 39.13472°N 85.8125°W / 39.13472; -85.8125 (39.134634, -85.812440)[3].

According to the United States Census Bureau, the town has a total area of 0.2 square miles (0.6 km²), all of it land.

Demographics

As of the census[1] of 2000, there were 391 people, 147 households, and 108 families residing in the town. The population density was 1,552.9 people per square mile (603.9/km²). There were 175 housing units at an average density of 695.0/sq mi (270.3/km²). The racial makeup of the town was 97.70% White, 0.77% African American, 0.26% Native American, 0.26% Asian, and 1.02% from two or more races. Hispanic or Latino of any race were 0.51% of the population.

There were 147 households out of which 38.8% had children under the age of 18 living with them, 59.2% were married couples living together, 10.2% had a female householder with no husband present, and 26.5% were non-families. 21.8% of all households were made up of individuals and 8.8% had someone living alone who was 65 years of age or older. The average household size was 2.66 and the average family size was 3.11.

In the town the population was spread out with 28.4% under the age of 18, 9.5% from 18 to 24, 30.2% from 25 to 44, 19.4% from 45 to 64, and 12.5% who were 65 years of age or older. The median age was 32 years. For every 100 females there were 101.5 males. For every 100 females age 18 and over, there were 101.4 males.

The median income for a household in the town was $36,364, and the median income for a family was $41,364. Males had a median income of $29,500 versus $20,333 for females. The per capita income for the town was $16,373. About 8.8% of families and 12.7% of the population were below the poverty line, including 19.4% of those under age 18 and 13.6% of those age 65 or over.

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