Fairmont, Nebraska

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Fairmont is a village in Fillmore County, Nebraska, United States. The population was 691 at the 2000 census.



Fairmont is located at 40°38′8″N 97°35′6″W / 40.63556°N 97.585°W / 40.63556; -97.585 (40.635526, -97.584928)[3].

According to the United States Census Bureau, the village has a total area of 0.7 square miles (1.8 km²), all of it land.


As of the census[1] of 2000, there were 691 people, 275 households, and 171 families residing in the village. The population density was 996.2 people per square mile (386.7/km²). There were 309 housing units at an average density of 445.5/sq mi (172.9/km²). The racial makeup of the village was 95.80% White, 0.14% African American, 0.72% Native American, 0.14% Asian, 1.45% from other races, and 1.74% from two or more races. Hispanic or Latino of any race were 3.04% of the population.

There were 275 households out of which 30.2% had children under the age of 18 living with them, 53.1% were married couples living together, 6.9% had a female householder with no husband present, and 37.8% were non-families. 33.8% of all households were made up of individuals and 21.1% had someone living alone who was 65 years of age or older. The average household size was 2.35 and the average family size was 3.02.

In the village the population was spread out with 25.8% under the age of 18, 4.3% from 18 to 24, 23.6% from 25 to 44, 23.0% from 45 to 64, and 23.3% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 82.3 males. For every 100 females age 18 and over, there were 79.4 males.

The median income for a household in the village was $35,658, and the median income for a family was $41,618. Males had a median income of $31,667 versus $18,125 for females. The per capita income for the village was $15,957. About 8.0% of families and 12.6% of the population were below the poverty line, including 13.8% of those under age 18 and 24.8% of those age 65 or over.


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