Fayette, Ohio

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Fayette is a village in Fulton County, Ohio, United States. The population was 1,340 at the 2000 census.



Fayette is located at 41°40′28″N 84°19′41″W / 41.67444°N 84.32806°W / 41.67444; -84.32806 (41.674579, -84.327924)[3].

According to the United States Census Bureau, the village has a total area of 0.9 square miles (2.4 km²), all of it land.


As of the census[2] of 2000, there were 1,340 people, 541 households, and 360 families residing in the village. The population density was 1,469.1 people per square mile (568.5/km²). There were 569 housing units at an average density of 623.8/sq mi (241.4/km²). The racial makeup of the village was 94.48% White, 0.15% African American, 0.30% Native American, 3.58% from other races, and 1.49% from two or more races. Hispanic or Latino of any race were 8.51% of the population.

There are 541 households out of which 34.2% have children under the age of 18 living with them, 49.9% were married couples living together, 11.3% had a female householder with no husband present, and 33.3% were non-families. 26.4% of all households were made up of individuals and 11.3% had someone living alone who was 65 years of age or older. The average household size was 2.48 and the average family size was 3.00.

In the village the population was spread out with 28.4% under the age of 18, 10.6% from 18 to 24, 30.0% from 25 to 44, 19.8% from 45 to 64, and 11.2% who were 65 years of age or older. The median age was 31 years. For every 100 females there were 93.6 males. For every 100 females age 18 and over, there were 88.0 males.

The median income for a household in the village was $32,115, and the median income for a family was $39,196. Males had a median income of $29,950 versus $23,077 for females. The per capita income for the village was $15,265. 9.7% of the population and 7.2% of families were below the poverty line. Out of the total population, 12.9% of those under the age of 18 and 9.7% of those 65 and older were living below the poverty line.

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