Galena, Ohio

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Galena is a village in Delaware County, Ohio, United States. The population was 305 at the 2000 census.



Galena is located at 40°12′55″N 82°52′54″W / 40.21528°N 82.88167°W / 40.21528; -82.88167 (40.215214, -82.881757)[3].

According to the United States Census Bureau, the village has a total area of 0.6 square miles (1.7 km²), of which, 0.6 square miles (1.6 km²) of it is land and 0.1 square miles (0.1 km²) of it (7.81%) is water.


As of the census[2] of 2000, there were 305 people, 122 households, and 89 families residing in the village. The population density was 509.8 people per square mile (196.3/km²). There were 132 housing units at an average density of 220.6/sq mi (84.9/km²). The racial makeup of the village was 97.70% White, 0.66% Native American, and 1.64% from two or more races. Hispanic or Latino of any race were 1.64% of the population.

There were 122 households out of which 32.0% had children under the age of 18 living with them, 61.5% were married couples living together, 5.7% had a female householder with no husband present, and 27.0% were non-families. 25.4% of all households were made up of individuals and 9.8% had someone living alone who was 65 years of age or older. The average household size was 2.50 and the average family size was 2.97.

In the village the population was spread out with 23.6% under the age of 18, 7.2% from 18 to 24, 29.8% from 25 to 44, 23.6% from 45 to 64, and 15.7% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 102.0 males. For every 100 females age 18 and over, there were 100.9 males.

The median income for a household in the village was $46,250, and the median income for a family was $49,500. Males had a median income of $38,750 versus $27,250 for females. The per capita income for the village was $20,163. About 4.8% of families and 9.6% of the population were below the poverty line, including 22.1% of those under the age of 18 and none of those 65 or over.

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