Geneva, Ohio

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Geneva is a city in Ashtabula County, Ohio, United States. The area which would become Geneva was originally settled in 1805, and was incorporated as a city in 1958. It is named after Geneva, New York. The city's population was 6,595 at the 2000 census.[1]



The area which would eventually be Geneva was first settled in 1805 by a handful of settlers from Charlotte, New York.[3] In 1806, settlers from Harpersfield, New York arrived and established Harpersfield Township, which included the present-day townships of Geneva, Trumbull and Hartsgrove.[3] However, in 1816, citizens of Harpersfield decided to withdraw from the township and form their own township, which then became Geneva Township, named after Geneva, New York.[3] In 1866, the town of Geneva then became a village, and, nearly one hundred years later, in 1958, Geneva was incorporated as a city.[3]


Geneva is located at 41°48′0″N 80°56′45″W / 41.8°N 80.94583°W / 41.8; -80.94583 (41.800098, -80.945784)[4], 45 miles (72 km) east of Cleveland and 55 miles (89 km) west of Erie, Pennsylvania.

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