Geneva-on-the-Lake, Ohio

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Geneva-on-the-Lake is a village in Ashtabula County, Ohio, United States. The population was 1,545 at the 2000 census.



Geneva-on-the-Lake is located at 41°51′28″N 80°56′47″W / 41.85778°N 80.94639°W / 41.85778; -80.94639 (41.857753, -80.946372)[3].

According to the United States Census Bureau, the village has a total area of 2.0 square miles (5.3 km²), of which, 2.0 square miles (5.3 km²) of it is land and 0.04 square miles (0.1 km²) of it (0.98%) is water.


As of the census[2] of 2000, there were 1,545 people, 665 households, and 395 families residing in the village. The population density was 760.9 people per square mile (293.9/km²). There were 1,167 housing units at an average density of 574.7/sq mi (222.0/km²). The racial makeup of the village was 96.18% White, 0.58% African American, 0.32% Native American, 0.32% Asian, 1.04% from other races, and 1.55% from two or more races. Hispanic or Latino of any race were 2.20% of the population. 24.5% were of German, 12.9% Irish, 10.4% English, 9.2% American and 7.8% Italian ancestry according to Census 2000.

There were 665 households out of which 30.2% had children under the age of 18 living with them, 38.5% were married couples living together, 15.8% had a female householder with no husband present, and 40.5% were non-families. 31.9% of all households were made up of individuals and 9.0% had someone living alone who was 65 years of age or older. The average household size was 2.32 and the average family size was 2.90.

In the village the population was spread out with 26.6% under the age of 18, 8.9% from 18 to 24, 31.0% from 25 to 44, 20.7% from 45 to 64, and 12.8% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 99.6 males. For every 100 females age 18 and over, there were 96.9 males.

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