Hampton, Nebraska

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Hampton is a village in Hamilton County, Nebraska, USA. The population was 439 at the 2000 census.



Hampton is located at 40°52′52″N 97°53′13″W / 40.88111°N 97.88694°W / 40.88111; -97.88694 (40.881062, -97.886919)[3].

According to the United States Census Bureau, the village has a total area of 0.3 square miles (0.9 km²), all of it land.


As of the census[1] of 2000, there were 439 people, 179 households, and 124 families residing in the village. The population density was 1,342.6 people per square mile (513.6/km²). There were 190 housing units at an average density of 581.1/sq mi (222.3/km²). The racial makeup of the village was 98.41% White, 0.23% African American, 0.68% Native American, and 0.68% from two or more races. Hispanic or Latino of any race were 0.23% of the population.

There were 179 households out of which 31.8% had children under the age of 18 living with them, 63.7% were married couples living together, 3.9% had a female householder with no husband present, and 30.7% were non-families. 26.8% of all households were made up of individuals and 17.9% had someone living alone who was 65 years of age or older. The average household size was 2.45 and the average family size was 3.01.

In the village the population was spread out with 25.5% under the age of 18, 5.7% from 18 to 24, 27.8% from 25 to 44, 21.4% from 45 to 64, and 19.6% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 98.6 males. For every 100 females age 18 and over, there were 100.6 males.

The median income for a household in the village was $42,692, and the median income for a family was $46,563. Males had a median income of $28,500 versus $20,250 for females. The per capita income for the village was $18,458. About 1.5% of families and 2.1% of the population were below the poverty line, including 4.7% of those under age 18 and 2.3% of those age 65 or over.

See also

Meyer v. Nebraska


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