Harrod, Ohio

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Harrod is a village in Allen County, Ohio, United States with a population of 491 as of the 2000 U.S. census. It is included in the Lima, Ohio Metropolitan Statistical Area.



Harrod is located at 40°42′30″N 83°55′13″W / 40.70833°N 83.92028°W / 40.70833; -83.92028 (40.708427, -83.920298).[3]

According to the United States Census Bureau, the village has a total area of 0.2 square miles (0.6 km²), all of it land.


As of the census[2] of 2000, there were 491 people, 173 households, and 135 families residing in the village. The population density was 2,193.1 people per square mile (861.7/km²). There were 178 housing units at an average density of 795.1/sq mi (312.4/km²). The racial makeup of the village was 98.37% White, 0.61% Native American, 0.41% from other races, and 0.61% from two or more races. Hispanic or Latino of any race were 1.63% of the population.

There were 173 households out of which 44.5% had children under the age of 18 living with them, 64.7% were married couples living together, 8.7% had a female householder with no husband present, and 21.4% were non-families. 19.7% of all households were made up of individuals and 6.4% had someone living alone who was 65 years of age or older. The average household size was 2.84 and the average family size was 3.24.

In the village the population was spread out with 31.6% under the age of 18, 8.6% from 18 to 24, 29.9% from 25 to 44, 21.0% from 45 to 64, and 9.0% who were 65 years of age or older. The median age was 32 years. For every 100 females there were 100.4 males. For every 100 females age 18 and over, there were 96.5 males.

The median income for a household in the village was $38,333, and the median income for a family was $43,611. Males had a median income of $31,369 versus $18,125 for females. The per capita income for the village was $15,422. About 4.8% of families and 7.0% of the population were below the poverty line, including 6.5% of those under age 18 and 10.5% of those age 65 or over.

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