Hedley, Texas

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Hedley is a city in Donley County, Texas, United States. The population was 379 at the 2000 census.



Hedley is located at 34°52′2″N 100°39′35″W / 34.86722°N 100.65972°W / 34.86722; -100.65972 (34.867099, -100.659761)[3].

According to the United States Census Bureau, the city has a total area of 0.7 square miles (1.9 km²), all of it land.


As of the census[1] of 2000, there were 379 people, 161 households, and 98 families residing in the city. The population density was 520.1 people per square mile (200.5/km²). There were 209 housing units at an average density of 286.8/sq mi (110.5/km²). The racial makeup of the city was 91.29% White, 1.85% African American, 1.58% Native American, 5.01% from other races, and 0.26% from two or more races. Hispanic or Latino of any race were 9.76% of the population.

There were 161 households out of which 24.8% had children under the age of 18 living with them, 49.7% were married couples living together, 8.1% had a female householder with no husband present, and 39.1% were non-families. 37.9% of all households were made up of individuals and 25.5% had someone living alone who was 65 years of age or older. The average household size was 2.35 and the average family size was 3.13.

In the city the population was spread out with 28.8% under the age of 18, 6.9% from 18 to 24, 19.0% from 25 to 44, 21.6% from 45 to 64, and 23.7% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 83.1 males. For every 100 females age 18 and over, there were 74.2 males.

The median income for a household in the city was $25,750, and the median income for a family was $39,375. Males had a median income of $22,500 versus $20,208 for females. The per capita income for the city was $11,568. About 10.8% of families and 20.4% of the population were below the poverty line, including 13.0% of those under age 18 and 40.5% of those age 65 or over.


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