Hopedale, Ohio

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Hopedale is a village in Harrison County, Ohio, United States. The population was 984 at the 2000 census.



Hopedale is located at 40°19′30″N 80°53′55″W / 40.325°N 80.89861°W / 40.325; -80.89861 (40.324867, -80.898719)[4].

According to the United States Census Bureau, the village has a total area of 0.7 square miles (1.9 km²), all of it land.


As of the census[3] of 2000, there were 984 people, 383 households, and 278 families residing in the village. The population density was 1,374.8 people per square mile (527.7/km²). There were 400 housing units at an average density of 558.8/sq mi (214.5/km²). The racial makeup of the village was 98.98% White, 0.61% African American, 0.10% Native American, and 0.30% from two or more races. Hispanic or Latino of any race were 0.51% of the population.

There were 383 households out of which 28.2% had children under the age of 18 living with them, 62.1% were married couples living together, 8.6% had a female householder with no husband present, and 27.4% were non-families. 23.2% of all households were made up of individuals and 14.6% had someone living alone who was 65 years of age or older. The average household size was 2.42 and the average family size was 2.83.

In the village the population was spread out with 21.3% under the age of 18, 4.7% from 18 to 24, 27.3% from 25 to 44, 22.4% from 45 to 64, and 24.3% who were 65 years of age or older. The median age was 43 years. For every 100 females there were 94.5 males. For every 100 females age 18 and over, there were 84.3 males.

The median income for a household in the village was $34,135, and the median income for a family was $38,558. Males had a median income of $35,263 versus $21,964 for females. The per capita income for the village was $16,536. About 9.8% of families and 11.8% of the population were below the poverty line, including 14.7% of those under age 18 and 8.5% of those age 65 or over.


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