Jarrettsville, Maryland

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Jarrettsville is a census-designated place (CDP) in Harford County, Maryland, United States. The population was 2,756 at the 2000 census.

Contents

Geography

Jarrettsville is located at 39°36′7″N 76°28′21″W / 39.60194°N 76.4725°W / 39.60194; -76.4725 (39.601954, -76.472404)[1].

According to the United States Census Bureau, the CDP has a total area of 8.7 square miles (22.6 km²), all of it land.

Demographics

As of the census[2] of 2000, there were 2,756 people, 900 households, and 781 families residing in the CDP. The population density was 315.8 people per square mile (121.9/km²). There were 918 housing units at an average density of 105.2/sq mi (40.6/km²). The racial makeup of the CDP was 97.21% White, 1.16% African American, 0.15% Native American, 0.29% Asian, 0.33% from other races, and 0.87% from two or more races. Hispanic or Latino of any race were 0.54% of the population.

There were 900 households out of which 43.7% had children under the age of 18 living with them, 77.6% were married couples living together, 6.4% had a female householder with no husband present, and 13.2% were non-families. 11.1% of all households were made up of individuals and 5.4% had someone living alone who was 65 years of age or older. The average household size was 3.05 and the average family size was 3.30.

In the CDP the population was spread out with 28.9% under the age of 18, 6.5% from 18 to 24, 26.4% from 25 to 44, 29.0% from 45 to 64, and 9.2% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 101.3 males. For every 100 females age 18 and over, there were 97.3 males.

The median income for a household in the CDP was $69,632, and the median income for a family was $81,771. Males had a median income of $51,524 versus $31,905 for females. The per capita income for the CDP was $29,246. None of the families and 1.4% of the population were living below the poverty line, including no under eighteens and 11.6% of those over 64.

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