Lannon, Wisconsin

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Lannon is a village in Waukesha County, Wisconsin, United States. The population was 1,009 at the 2000 census.



Lannon is located at 43°9′1″N 88°9′52″W / 43.15028°N 88.16444°W / 43.15028; -88.16444 (43.150288, -88.164568).[3]

According to the United States Census Bureau, the village has a total area of 2.4 square miles (6.3 km²), all of it land.


As of the census[2] of 2000, there were 1,009 people, 425 households, and 282 families residing in the village. The population density was 413.0 people per square mile (159.7/km²). There were 434 housing units at an average density of 177.7/sq mi (68.7/km²). The racial makeup of the village was 97.92% White, 0.50% African American, 0.40% Native American, 0.10% Asian, 0.10% from other races, and 0.99% from two or more races. Hispanic or Latino of any race were 1.59% of the population.

There were 425 households out of which 27.1% had children under the age of 18 living with them, 55.3% were married couples living together, 6.4% had a female householder with no husband present, and 33.6% were non-families. 29.2% of all households were made up of individuals and 9.4% had someone living alone who was 65 years of age or older. The average household size was 2.37 and the average family size was 2.95.

In the village the population was spread out with 22.9% under the age of 18, 5.9% from 18 to 24, 29.8% from 25 to 44, 27.8% from 45 to 64, and 13.5% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 110.6 males. For every 100 females age 18 and over, there were 104.2 males.

The median income for a household in the village was $44,375, and the median income for a family was $54,107. Males had a median income of $36,250 versus $25,583 for females. The per capita income for the village was $21,041. About 4.4% of families and 6.1% of the population were below the poverty line, including 8.7% of those under age 18 and 8.4% of those age 65 or over.

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