Lima, Oklahoma

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Lima is a town in Seminole County, Oklahoma, United States. The population was 74 at the 2000 census.



Lima is located at 35°10′24″N 96°35′54″W / 35.17333°N 96.59833°W / 35.17333; -96.59833 (35.173362, -96.598337)[3]. According to the United States Census Bureau, the town has a total area of 0.5 square miles (1.2 km²), all of it land.


As of the census[1] of 2000, there were 74 people, 30 households, and 18 families residing in the town. The population density was 159.9 people per square mile (62.1/km²). There were 39 housing units at an average density of 84.3/sq mi (32.7/km²). The racial makeup of the town was 43.24% White, 36.49% African American, 5.41% Native American, and 14.86% from two or more races. Hispanic or Latino of any race were 2.70% of the population.

There were 30 households out of which 13.3% had children under the age of 18 living with them, 40.0% were married couples living together, 16.7% had a female householder with no husband present, and 36.7% were non-families. 33.3% of all households were made up of individuals and 10.0% had someone living alone who was 65 years of age or older. The average household size was 2.47 and the average family size was 3.05.

In the town the population was spread out with 28.4% under the age of 18, 5.4% from 18 to 24, 18.9% from 25 to 44, 33.8% from 45 to 64, and 13.5% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 117.6 males. For every 100 females age 18 and over, there were 89.3 males.

The median income for a household in the town was $18,750, and the median income for a family was $15,625. Males had a median income of $23,125 versus $14,375 for females. The per capita income for the town was $6,473. There were 47.4% of families and 59.7% of the population living below the poverty line, including 70.4% of under eighteens and 40.0% of those over 64.


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